A body of mass 0.4 kg falls through air with an acceleration of 5 ms−2. The frictional force of air on the body is :
0.02 N
1 N
2 N
0.2 N
A
2 N
B
0.2 N
C
1 N
D
0.02 N
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Solution
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In general if there is no friction acceleration for free falling is a = g = 10m/s2
now due to friction anet=5m/s2
Retardation due to friction =afriction10−5=5m/s2
Friction force f =mafriction=0.4×5=2N
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