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A body of mass 10 kg is dropped to the ground from a height of 10 metres. The work done by the gravitational force is $$ ( g = 9.8 m / sec^2 ) $$

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Solution

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Work done is given by:

$$W=Fs$$

Where F is the force and s is the displacement

As the body moves in the direction of force, therefore work done by gravitational force will be positive.

$$ W = Fs =mgh = 10 \times 9.8 \times 10 = 980 J $$

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