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>>Motion in a Straight Line
>>Uniformly Accelerated Motion
>> $A body of mass 2 kg fall vertically, pas$

Question

A body of mass $2 k g$ fall vertically, passing through two points $A$ and $B$ . The speeds of the body as it passes $A$ and $B$ are $1 m / s$ and $4 m / s$ respectively. The resistance against which the body falls is $9.6 N$ . What is the distance $A B$ ?

A

$2 m$

B

$3 m$

C

$6 m$

D

$1.5 m$

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Updated on : 2022-09-05

Solution

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Correct option is D)

$u = 1 \frac{m}{s}$

$v = 4 \frac{m}{s}$

$a = \frac{F}{m}$

$a = \frac{9 . 6}{2} = 4.8 \frac{m}{s ^{2}}$

using

$v^{2} = u^{2} + 2 a s$

$4^{2} = 1^{2} + 2 \times 4.8 \times S$

$S = 1.5625 m$

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