A body of mass 2kg fall vertically, passing through two points A and B. The speeds of the body as it passes A and B are 1m/s and 4m/s respectively. The resistance against which the body falls is 9.6N. What is the distance AB?

2m

3m

1.5m

6m

A

6m

B

2m

C

1.5m

D

3m

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Solution

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u=1ms

v=4ms

a=Fm

a=9.62=4.8ms2

using

v2=u2+2as

42=12+2×4.8×S

S=1.5625m

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