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# A body of mass 2 kg fall vertically, passing through two points A and B. The speeds of the body as it passes A and B are 1 m/s and 4 m/s respectively. The resistance against which the body falls is 9.6 N. What is the distance AB?2 m3 m1.5 m6 m

A
6 m
B
2 m
C
1.5 m
D
3 m
Solution
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#### u=1msv=4msa=Fma=9.62=4.8ms2usingv2=u2+2as 42=12+2×4.8×S S=1.5625m

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