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Laws of Motion
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Newton's Second Law of Motion
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A body of mass 'm' and velocity 'u' stri
Question
A body of mass 'm' and velocity 'u' strikes a wall and rebounds with velocity 'v'. The change in momentum is:
A
m
(
v
−
u
)
B
m
(
u
−
v
)
C
−
m
(
v
+
u
)
D
none of these
Medium
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Updated on : 2022-09-05
Solution
Verified by Toppr
Correct option is C)
Given :
u
=
u
x
^
v
=
−
v
x
^
Thus change in momentum
Δ
P
=
m
(
v
−
u
)
∴
Δ
P
=
m
(
−
v
−
u
)
=
−
m
(
u
+
v
)
x
^
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