A body of mass M collides against a wall with velocity V and rebounds with the same speed- Its magnitude of change in momentum is-MV02MVdfrac-MV-2-

Question

Toppr Admin · Accepted Answer

Given that the-xA0-xA0-body of mass M-xA0-velocity-xA0-V-xA0-xA0-rebounds with the same speed- -xA0-Change of momentum -M-xD7-xA0-Change in velocity-M-V-x2212-x2212-V-2MVThus- the change in momentum of the rebounding ball is 2MV-

A body of mass $M$ collides against a wall with velocity $V$ and rebounds with the same speed. Its magnitude of change in momentum is:
$M V$
$0$
$2 M V$
$\frac{M V}{2}$

Given that the body of mass M, velocity V rebounds with the same speed.
Change of momentum $= M \times$ (Change in velocity)
$= M (V - (- V)) = 2 M V$
Thus, the change in momentum of the rebounding ball is $2 M V$ .

A body of mass M collides against a wall with velocity V and rebounds with the same speed. Its magnitude of change in momentum is:MV02MVMV2

Given that the body of mass M, velocity V rebounds with the same speed. Change of momentum =M× (Change in velocity)=M(V−(−V))=2MVThus, the change in momentum of the rebounding ball is 2MV.

A body of mass $M$ collides against a wall with velocity $V$ and rebounds with the same speed. Its magnitude of change in momentum is:
$M V$
$0$
$2 M V$
$\frac{M V}{2}$

Given that the body of mass M, velocity V rebounds with the same speed.
Change of momentum $= M \times$ (Change in velocity)
$= M (V - (- V)) = 2 M V$
Thus, the change in momentum of the rebounding ball is $2 M V$ .