0
You visited us 0 times! Enjoying our articles? Unlock Full Access!
Question

A body of mass 'm' is raised to a height 10R from the surface of earh, where 'R' is the radius of earth. The increase in potential energy is (G= universal constant of gravitation, M=mass of earth and g= acceleration due to gravity).
  1. GMm11R
  2. mgR11G
  3. GMm10R
  4. 10GMm11R

A
GMm10R
B
10GMm11R
C
mgR11G
D
GMm11R
Solution
Verified by Toppr

Potential energy at point U=GMmr
where r is the distance of the point from the earth surface.
Thus potential energy at earth surface i.e. r=R, U1=GMmR
Potential energy at a height 10R above earth surface i.e. r=11R, U2=GMm11R
Increase in potential energy ΔU=U2U1
Or ΔU=GMm11R(GMmR)
Or ΔU=GMmR[111+1]
ΔU=10GMm11R

Was this answer helpful?
0
Similar Questions
Q1
A body of mass 'm' is raised to a height 10R from the surface of earh, where 'R' is the radius of earth. The increase in potential energy is (G= universal constant of gravitation, M=mass of earth and g= acceleration due to gravity).
View Solution
Q2
A body of mass 'm' is raised from the surface of the earth to a height 'nR' (R- radius of earth). Magnitude of the change in the gravitational potential energy of the body is (g-acceleration due to gravity on the surface of earth)
View Solution
Q3
The radius of the earth is R and acceleration due to gravity at its surface is g. If a body of mass m is sent to a height R6 from the earth's surface, the potential energy increases by
View Solution
Q4
A body of mass m is raised from the surface of the earth to a height nR (R-radius of earth). Magnitude of the change in the gravitational potential energy of the body is (g- acceleration due to gravity on the surface of earth) :
View Solution
Q5
The change in Gravitational potential energy when a body of mass m is raised to a height nR from the Earth’s surface is (R= radius of the earth, g= acceleration due to gravity on the surface of Earth)
View Solution