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Question

- 38ms−1
- 83ms−1
- 43ms−1
- 163ms−1

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Solution

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Let total distance be 2x

X is traveled by 2 m/s and x/2 by 3m/s and remaining x/2 by 5 m/s.

Vavg.=Total distanceTotal time

Vavg.=2xx2+x6+x10

Vavg.=2.608m/s

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