A body of mass m moving along a straight line covers half the distance with a speed of $2 m s^{- 1}$ . The remaining half of distance is covered in two equal time intervals with a speed of $3$ $m s^{- 1}$ and $5$ $m s^{- 1}$ respectively. The average speed of the particle for the entire journey is?
$\frac{3}{8} m s^{- 1}$
$\frac{8}{3} m s^{- 1}$
$\frac{4}{3} m s^{- 1}$
$\frac{16}{3} m s^{- 1}$

Question

A body of mass m moving along a straight line covers half the distance with a speed of $2 m s^{- 1}$ . The remaining half of distance is covered in two equal time intervals with a speed of $3$ $m s^{- 1}$ and $5$ $m s^{- 1}$ respectively. The average speed of the particle for the entire journey is?
$\frac{3}{8} m s^{- 1}$
$\frac{8}{3} m s^{- 1}$
$\frac{4}{3} m s^{- 1}$
$\frac{16}{3} m s^{- 1}$

Toppr Admin · Accepted Answer

Let total distance be 2xX is traveled by 2 m-s and x-2 by 3m-s and remaining x-2 by 5 m-s-Vavg-Total-xA0-distanceTotal-xA0-timeVavg-2xx2-x6-x10Vavg-2-608m-s

Let total distance be 2xX is traveled by 2 m/s and x/2 by 3m/s and remaining x/2 by 5 m/s.Vavg.=Total distanceTotal timeVavg.=2xx2+x6+x10Vavg.=2.608m/s

Let total distance be $2 x$
X is traveled by 2 m/s and x/2 by 3m/s and remaining x/2 by 5 m/s.
$V_{a v g .} = \frac{T o t a l d i s t a n c e}{T o t a l t i m e}$

$V_{a v g .} = \frac{2 x}{\frac{x}{2} + \frac{x}{6} + \frac{x}{10}}$

$V_{a v g .} = 2.608 m / s$