A body starts from rest with a uniform acceleration of 2m/s $^{2}$ for 10 sec , with moves with constant speed for 30 sec then decelerates by 4 m/s $^{2}$ to zero . What is the distance covered by the body?

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Answer 1

$u = 0$

$a$ = $2 m / S^{2}$

$t = 10 S e c o n d$

$S_{1}$ = $u t + 0.5 a t^{2}$

$s_{1}$ = $0 + 0.5 \times 2 \times 100$ = $100 m$

$S_{2}$ = $v + 2$

$v = u + a t$ = $0 + 20$ = $20 m / s$

$s_{2}$ = $20 \times 30$ = $600$ m

$0^{2} - v^{2}$ = $2 (- a) s_{3}$

$s_{3}$ = $\frac{4 0 0}{8}$ =50m

$s = s_{1} + s_{2} + s_{3}$ = $100 + 600 + 50$ = $750$

Answer 2

u = 0

a

=

2 m / S^{2}

t = 10 S e c o n d

S_{1}

=

u t + 0.5 a t^{2}

s_{1}

=

0 + 0.5 \times 2 \times 100

=

100 m

S_{2}

=

v + 2

v = u + a t

=

0 + 20

=

20 m / s

s_{2}

=

20 \times 30

=

600

m

0^{2} - v^{2}

=

2 (- a) s_{3}

s_{3}

=

\frac{4 0 0}{8}

=50m

s = s_{1} + s_{2} + s_{3}

=

100 + 600 + 50

=

750

A body starts from rest with a uniform acceleration of 2m/s $^{2}$ for 10 sec , with moves with constant speed for 30 sec then decelerates by 4 m/s $^{2}$ to zero . What is the distance covered by the body?

750 m

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950 m

1050 m

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A body starts from rest with a uniform acceleration of 2m/s2 for 10 sec , with moves with constant speed for 30 sec then decelerates by 4 m/s2 to zero . What is the distance covered by the body?

750 m

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u=0 a=2m/S2 t=10Second S1​=ut+0.5at2 s1​=0+0.5×2×100=100m S2​=v+2 v=u+at=0+20=20m/s s2​=20×30=600 m 02−v2=2(−a)s3​ s3​=8400​=50m s=s1​+s2​+s3​=100+600+50=750

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