−dTdt=k(T−To)
T= Temp of body
To= Temp. of surrounding =25oC
t=10min=10(60)=600sec
∫6050dT(T−To)=−k[t]600o
2.303kloge[T−To]6050=−k[600]
⇒2.303kloge[60−2550−25]=−600
⇒2.303kloge[3025]=−600 ...(1)
Now suppose for next to min, temp falls from 50 to T
2.303kloge[T−To]50T=−600
2.303kloge[50−25T−25]=−600 ...(2)
from (1) & (2)
loge(3525)=loge(25T−25)
3525=25(T−25)
7T−175=125
7T=125+175
=300
T=3007≈43oC