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Question

# A body travelling with uniform acceleration crosses two points A and B with velocities 20 m/sec and 30 m/sec respectively then the speed of the body at mid point of A and B is25.5 m/sec24 m/sec10√6 m/sec25 m/sec

A
24 m/sec
B
106 m/sec
C
25.5 m/sec
D
25 m/sec
Solution
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#### Let the acceleration of the car is =a and the distance between A and B is =dv2−u2=2adGiven,v=30m/s and u=20m/s2ad=302−202ad=(900−400)2=250when the car is at the mid point of AB then let the speed of the car is v1v21−202=2a(d2)v21=ad+400=250+400=650therefore v1 is =25.5m/s

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