Question

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Updated on : 2022-09-05

Solution

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Correct option is B)

Let the acceleration of the car is $=a$ and the distance between $A$ and $B$ is $=d$

$v_{2}−u_{2}=2ad$

Given,

$v=30m/s$ and $u=20m/s$

$2ad=30_{2}−20_{2}$

$ad=2(900−400) =250$

when the car is at the mid point of $AB$ then let the speed of the car is

$v_{1}$

$v_{1}−20_{2}=2a(2d )$

$v_{1}=ad+400=250+400=650$

therefore

$v_{1}$ is $=25.5m/s$

Solve any question of Motion in a Straight Line with:-

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