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Question

A body travelling with uniform acceleration crosses two points A and B with velocities 20 m/sec and 30 m/sec respectively then the speed of the body at mid point of A and B is
  1. 25.5 m/sec
  2. 24 m/sec
  3. 106 m/sec
  4. 25 m/sec

A
24 m/sec
B
106 m/sec
C
25.5 m/sec
D
25 m/sec
Solution
Verified by Toppr


Let the acceleration of the car is =a and the distance between A and B is =d

v2u2=2ad

Given,

v=30m/s and u=20m/s

2ad=302202

ad=(900400)2=250

when the car is at the mid point of AB then let the speed of the car is
v1

v21202=2a(d2)

v21=ad+400=250+400=650

therefore

v1 is =25.5m/s

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