A body travelling with uniform acceleration crosses two points A and B with velocities 20m/sec and 30m/sec respectively then the speed of the body at mid point of A and B is
A
25m/sec
B
25.5m/sec
C
24m/sec
D
106m/sec
Medium
Open in App
Updated on : 2022-09-05
Solution
Verified by Toppr
Correct option is B)
Let the acceleration of the car is =a and the distance between A and B is =d
v2−u2=2ad
Given,
v=30m/s and u=20m/s
2ad=302−202
ad=2(900−400)=250
when the car is at the mid point of AB then let the speed of the car is
v1
v12−202=2a(2d)
v12=ad+400=250+400=650
therefore
v1 is =25.5m/s
Solve any question of Motion in a Straight Line with:-