A body weighs 700 N on the surface of the earth- What is its weight on the surface of a planet- whose mass is - 1 - 7 -th and radius is - 1 - 2 - as that of the earth-400 N300 N700 N500 N

Question

Toppr Admin · Accepted Answer

F-GMmR2-700NIf M-x2192-M7R-x2192-R2-x2234-F1-GMm-47R2-47F-47-x2217-700N-400N

A body weighs $700 N$ on the surface of the earth. What is its weight on the surface of a planet, whose mass is $1 / 7$ th and radius is $1 / 2$ as that of the earth?
$400 N$
$300 N$
$700 N$
$500 N$

$F = \frac{G M m}{R^{2}} = 700 N$
If $M \to \frac{M}{7} R \to \frac{R}{2} ∴ F^{1} = \frac{G M m .4}{7 R^{2}} = \frac{4}{7} F = \frac{4}{7} * 700 N = 400 N$

A body weighs 700N on the surface of the earth. What is its weight on the surface of a planet, whose mass is 1/7th and radius is 1/2 as that of the earth?400N300N700N500N

F=GMmR2=700NIf M→M7R→R2∴F1=GMm.47R2=47F=47∗700N=400N

A body weighs $700 N$ on the surface of the earth. What is its weight on the surface of a planet, whose mass is $1 / 7$ th and radius is $1 / 2$ as that of the earth?
$400 N$
$300 N$
$700 N$
$500 N$

$F = \frac{G M m}{R^{2}} = 700 N$
If $M \to \frac{M}{7} R \to \frac{R}{2} ∴ F^{1} = \frac{G M m .4}{7 R^{2}} = \frac{4}{7} F = \frac{4}{7} * 700 N = 400 N$