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# A body weighs 72 N on the surface of earth. What is the gravitational force on it due to earth at a height equal to half the radius of the earth from the surface?72 N28 N16 N32 N

A
16 N
B
28 N
C
32 N
D
72 N
Solution
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#### The correct option is D32 NAt the surface of Earth, weight W=72N∴F=mg=72Nm=7210=7.2kgNow, at some height, h acceleration due to gravity is given as g′=g(1+hR)2Here, h=R2g′=g(1+12)2=49g=4.44m/s2Now, the force experienced by the body at half of the radius of the earth is given by: F′=mg′=7.2×4.44=31.97N≈32N

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