A body weighs 72N on the surface of earth. What is the gravitational force on it due to earth at a height equal to half the radius of the earth from the surface?
A
72N
B
28N
C
16N
D
32N
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Solution
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The correct option is D32N
At the surface of Earth, weight W=72N
∴F=mg=72N
m=7210=7.2kg
Now, at some height, h acceleration due to gravity is given as
g′=g(1+hR)2
Here, h=R2
g′=g(1+12)2=49g=4.44m/s2
Now, the force experienced by the body at half of the radius of the earth is given by:
F′=mg′=7.2×4.44=31.97N≈32N
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A body weighs 72N on the surface of the earth. What will be the force of gravity acting on the body at a height equal to half the radius of the earth above the earth's surface?
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A body weight 72N on the surface of the earth. What is the gravitational force acting on it due to the earth at a height equal to half the radius of the earth from the surface?