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A body weighs 72 N on the surface of earth. What is the gravitational force on it due to earth at a height equal to half the radius of the earth from the surface?

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Solution

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At the surface of Earth, weight W=72N

∴F=mg=72N

m=7210=7.2kg

Now, at some height, h acceleration due to gravity is given as

g′=g(1+hR)2

Here, h=R2

g′=g(1+12)2=49g=4.44m/s2

Now, the force experienced by the body at half of the radius of the earth is given by:

F′=mg′=7.2×4.44=31.97N≈32N

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