A body weighs 72N on the surface of the earth. What is the gravitational force on it at a height equal to half the radius of the earth from the surface?
72N
28N
16N
32N
A
28N
B
16N
C
72N
D
32N
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Solution
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Lrt Re be the radius of earth
Given h=Re/2
Since h is comparable to Re
So, gh=GM(Re+h)2
Putting h=Re/2,we get
⇒gh=49×GMR2e=4g9
Where g is acceleration due to gravity at the surface of earth
Therefore weight at a height equal to half of the earth's radius =49×72=32N
Hence correct answer is option D
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