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Question

A body weighs 72N on the surface of the earth. What is the gravitational force on it due to the earth at a height equal to half the radius of the earth?
  1. 28 N
  2. 32 N
  3. 72 N
  4. 16 N.

A
16 N.
B
72 N
C
32 N
D
28 N
Solution
Verified by Toppr

Weight of body on the surface of the earth =mg=72N
Acceleration due to gravity at height h is
gh=gR2E(RE+h)2

Substitute h=RE2 in above expression:
gh=gR2E(RE+RE2)2
=49g

Gravitational force on body at height h is
F=mgh

=m×49g=49×mg

=49×72N=32N

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