A body weighs W newton at the surface of the earth. Its weight at a height equal to half the radius of the earth will be:

W2

2W3

4W9

W4

A

W4

B

W2

C

2W3

D

4W9

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Solution

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At the surface

W=GMmR2......(I)

W′=GMm(3R2)2.......(II)

WW′=GMmR2GMm9R2/4

⇒WW′=94

⇒W′=4W9

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