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Question

# A body weighs W newton at the surface of the earth. Its weight at a height equal to half the radius of the earth will be:W22W34W9W4

A
W4
B
W2
C
2W3
D
4W9
Solution
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#### At the surfaceW=GMmR2......(I)W′=GMm(3R2)2.......(II)WW′=GMmR2GMm9R2/4⇒WW′=94⇒W′=4W9

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