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A body weight $54 k g$ f on the surface of Earth.How much will it weigh on the surface of mars whose mass is $1 / 9$ and the radius is $1 / 2$ of that of earth ?

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Solution

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$g = \frac{G M^{'}}{R^{' 2}}$

$= \frac{G M}{q {(\frac{R}{2})}^{2}}$

$g^{'} \leq \frac{4 G m}{g} g$

$w = 54 \times \frac{4}{9} \times 9.8$

$= 24 \times 9.8$
$W = 235.2 M$

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