A body weight W Newton at the surface of the earth. Its weight at a height equal to half the radius of the earth will be :

W2

2W3

4W9

W4

A

4W9

B

W2

C

2W3

D

W4

Open in App

Solution

Verified by Toppr

Given, R=6400km,w=mg⇒g=wm

Now the weight of the body at the height is 12R

g′=g(1−dR)

So the weight of the body at the 12R

W′=W(1−R2R)=WR2R)=W2

Was this answer helpful?

12

Similar Questions

Q1

A body weight W Newton at the surface of the earth. Its weight at a height equal to half the radius of the earth will be :

View Solution

Q2

A body weighs W newton at the surface of the earth. Its weight at a height equal to half the radius of the earth will be:

View Solution

Q3

A body weighs w at the surface of the earth. Its weight at a height equal to half the radius of the earth will be:-

View Solution

Q4

A person goes to height equal to 2R from surface of earth (where R is radius of earth), weight of the person at this height is W1 and weight of person at surface of earth is W2, then W1W2 will be

View Solution

Q5

Weight of a body on earth's surface is W. At a depth half way to the centre of the earth, it will be (assuming uniform density in earth).