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Question

A boy standing between two cliffs claps and hears 2 echoes after 2s and 2.5 s respectively. If the velocity of sound is 330 ms1, find the distance between he two cliffs :
  1. 742.50 m
  2. 274.50 m
  3. 442.50 m
  4. 472.50 m

A
274.50 m
B
472.50 m
C
442.50 m
D
742.50 m
Solution
Verified by Toppr

Let d1 and d2 be the distances of cliffs from the boy .
for first echo , which is heard after 2s ,
total distance travelled by sound =2d1 ,
given v=330m/s ,
we have , distance=speed×time ,
2d1=330×2 ,
or d1=660/2=330m ,
for second echo , which is heard after 2.5s ,
total distance travelled by sound =2d2 ,
given v=330m/s ,
we have , distance=speed×time ,
2d2=330×2.5 ,
or d2=825/2=412.5m ,
therefore , distance between cliffs , d=d1+d2=330+412.5=742.5m

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