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Correct option is A)

Let initial velocity be $v$.

So, final velocity is $v/2$.

Energy lost is $21 mv_{2}−21 m(v/2)_{2}=21 m(43 v_{2})$

Remaining energy $=41 (1/2mv_{2}).$

Since, $43 KE$ is lost in $15cm$ penetration,

Hence $41 KE$ would penetrate to $315 =5cm$

So, the distance further travelled by the bullet before coming to rest $=5cm.$

So, final velocity is $v/2$.

Energy lost is $21 mv_{2}−21 m(v/2)_{2}=21 m(43 v_{2})$

$=43 (21 mv_{2})$

Remaining energy $=41 (1/2mv_{2}).$

Since, $43 KE$ is lost in $15cm$ penetration,

Hence $41 KE$ would penetrate to $315 =5cm$

So, the distance further travelled by the bullet before coming to rest $=5cm.$

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