Question

A bullet is moving at a speed of $367m/s$ when it embeds into a lump of moist clay. The bullet penetrates for a distance of $0.0621m$. Determine the acceleration of the bullet while moving into the clay. (Assume a uniform acceleration.)

• A. $1.08\times {10}^6$ $\frac{m}{s^2}$
• B. $-1.08\times {10}^6$ $\frac{m}{s^2}$
• C. $-1.08\times {10}^8$ $\frac{m}{s^2}$
• D. $-1.08\times {10}^7$ $\frac{m}{s^2}$

Answer 1

Answer: (B)

Here, initial velocity of bullet is $u=367m/s$ and final velocity is $v=0m/s$.

Distance traveled by bullet is $d=0.0621m$

If $a$ be the acceleration of bullet.

Using $v^2-u^2=2ad$

$0^2-(367{)}^2=2a(0.0621)$

$⟹$ $a=-1.08\times {10}^{-6}m/s^2$

(negative sign indicates deceleration of bullet means it slows down).