A bullet moving with a speed of 100- ms-1- can just penetrate into two planks of equal thickness- Then- the number of such planks the bullet will penetrate- speed is doubled will be20864

Question

Toppr Admin · Accepted Answer

12mv2-n-F-d-x21D2-n-x221D-v2Thus-If v is doubled- n will become four times-Therefore the bullet will penetrate 8 planks-

A bullet moving with a speed of $100 m s^{- 1}$ can just penetrate into two planks of equal thickness. Then, the number of such planks the bullet will penetrate, if speed is doubled will be
20
8
6
4

$\frac{1}{2} m v^{2} = n (F . d)$
$\Rightarrow n \propto v^{2}$
Thus,
If v is doubled, n will become four times.
Therefore the bullet will penetrate 8 planks.

A bullet moving with a speed of 100ms−1 can just penetrate into two planks of equal thickness. Then, the number of such planks the bullet will penetrate, if speed is doubled will be20864

12mv2=n(F.d)⇒n∝v2Thus,If v is doubled, n will become four times.Therefore the bullet will penetrate 8 planks.

A bullet moving with a speed of $100 m s^{- 1}$ can just penetrate into two planks of equal thickness. Then, the number of such planks the bullet will penetrate, if speed is doubled will be
20
8
6
4

$\frac{1}{2} m v^{2} = n (F . d)$
$\Rightarrow n \propto v^{2}$
Thus,
If v is doubled, n will become four times.
Therefore the bullet will penetrate 8 planks.