A bullet moving with a speed of $100ms_{−1}$ can just penetrate into two planks of equal thickness. Then, the number of such planks the bullet will penetrate, if speed is doubled will be

A

6

B

20

C

4

D

8

Hard

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Solution

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Correct option is D)

$21 mv_{2}=n(F.d)$ $⇒n∝v_{2}$ Thus, If v is doubled, n will become four times. Therefore the bullet will penetrate 8 planks.

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