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Question

A bus started its journey and reached different places with a speed of $$60$$ km/hour. The journey is shown in given figure.

Find out the time taken by the bus to reach E to G.

Solution
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$$Time = \dfrac{distance}{speed}$$
therefore

$$Total distance=EG=EF+FG=(4830+2550) \ km$$

$$\therefore time \ required=\dfrac{4830+2550}{60}=\dfrac{7380}{60}=123 hr$$

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