A bus starting from rest moves with a uniform acceleration of $$0.1 ms^{-2}$$ for $$2$$ minutes. Find
(a) the speed acquired,
(b) the distance travelled.
(a) Initial velocity of the bus $$u = 0$$ (Bus is at rest).
Acceleration, $$a = 0.1 ms^{-2}$$
Time $$t = 2$$ minutes $$= 120$$ seconds.
Let the speed of bus be $$‘V’$$
$$\therefore a=\dfrac{v-u}{t}$$
$$0.1=\dfrac{v.0}{120}$$
$$\therefore v = 12m/s$$.
(b) As per third law of motion:
$$v^{2} – u^{2} = 2as$$
$$(12)^{2} – (0)^{2} = 2(0. 1)s$$
$$\therefore s = 720 m$$.
The speed of acquired by bus $$= 12 m/s$$.
The distance travelled $$= 720 m$$.