0
You visited us 0 times! Enjoying our articles? Unlock Full Access!
Question

A bus starts from rest and moves with a uniform acceleration of 1ms2. A boy 10m behind the bus at the start runs at a constant speed and catches the bus in 10s. Speed of the boy is :
  1. 10ms1
  2. 1ms1
  3. 6ms1
  4. 4ms1

A
1ms1
B
4ms1
C
6ms1
D
10ms1
Solution
Verified by Toppr


Solution 2

Distance travelled by bus in 10s12×1×102=50m
D = Distance boy has to cover =10+50=60m
Speed of boy =DT=6010=6 m/s


69127_2349_ans_89cb0ff35b4e45f19195c896784b1622.PNG

Was this answer helpful?
3
Similar Questions
Q1
A bus starts from rest and moves with a uniform acceleration of 1ms2. A boy 10m behind the bus at the start runs at a constant speed and catches the bus in 10s. Speed of the boy is :
View Solution
Q2
A bus is beginning to move with an acceleration of 1 m/s2. A boy who is 48 m behind the bus starts running with constant speed of 10 m/s. The earliest time when the boy can catch the bus is
View Solution
Q3

A bus starts to move with acceleration 1m/s^2. A man who is 48 m behind the bus runs to catch it with a constant velocity of 10 m/sec. In how much time he will catch the bus?

View Solution
Q4
A bus at rest starts accelerating at 1 m/s. A man 50 m behind it runs to catch the bus. At what minimum speed should he run to catch the bus
View Solution
Q5
A boy stands at a distance 'd' behind the bus. The bus and boy start moving simultaneously; the boy with an initial and constant velocity of 'v' and the bus starts from rest with an acceleration of 'a' What is the minimum value of 'v' such that the boy successfully catches the bus?
View Solution