A can do a piece of work in 20 days which B can do in 12 days- B worked it 9 days- A can finish the remaining work in how many days -

Question

Toppr Admin · Accepted Answer

B-apos-s 9 day-apos-s work - -112-xD7-9-34Remaining work - 1-x2212-34-14120 work is finished by A in 1 day-14 work is finished by A in -20-xD7-14-5-xA0-days

A can do a piece of work in 20 days which B can do in 12 days. B worked at it for 9 days. A can finish the remaining work in how many days ?

B's 9 day's work = $(\frac{1}{12} \times 9) = \frac{3}{4}$

Remaining work = $1 - \frac{3}{4} = \frac{1}{4}$

$\frac{1}{20}$ work is finished by A in 1 day.

$\frac{1}{4}$ work is finished by A in $(20 \times \frac{1}{4}) = 5 d a y s$

A can do a piece of work in 20 days which B can do in 12 days. B worked at it for 9 days. A can finish the remaining work in how many days ?

B's 9 day's work = (112×9)=34Remaining work = 1−34=14120 work is finished by A in 1 day.14 work is finished by A in (20×14)=5 days

B's 9 day's work = $(\frac{1}{12} \times 9) = \frac{3}{4}$

Remaining work = $1 - \frac{3}{4} = \frac{1}{4}$

$\frac{1}{20}$ work is finished by A in 1 day.

$\frac{1}{4}$ work is finished by A in $(20 \times \frac{1}{4}) = 5 d a y s$