A capacitor consists of two metal plates each 10cm by 20cm; they are separated by a 2.0mm thick insulator with dielectric constant 4.1 and dielectric strength 6.0107 V/m. What is the capacitance in pF(10−12F)?
75
100
240
360
A
100
B
240
C
75
D
360
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Solution
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C=kϵ0Ad
C=4.1×8.85×10−12×10×20×10−42×10−3
C=361≈360pF
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