A capacitor is charged to store an energy U. The charging battery is disconnected. An identical capacitor is now connected to the first capacitor in parallel. The energy in each of the capacitors is :
3 U/2
U
U/4
U/2

Question

A capacitor is charged to store an energy U. The charging battery is disconnected. An identical capacitor is now connected to the first capacitor in parallel. The energy in each of the capacitors is :
3 U/2
U
U/4
U/2

Toppr Admin · Accepted Answer

Energy stored in a capacitor is U-Q22C-As the battery is disconnected- total charge Q is shared equally by two capacitors-So energy of each capacitor-xA0- -Q-2-22C-14Q22C-U4-

A capacitor is charged to store an energy U. The charging battery is disconnected. An identical capacitor is now connected to the first capacitor in parallel. The energy in each of the capacitors is :3 U/2UU/4U/2

Energy stored in a capacitor is U=Q22C.As the battery is disconnected, total charge Q is shared equally by two capacitors.So energy of each capacitor =(Q/2)22C=14Q22C=U4.

A capacitor is charged to store an energy U. The charging battery is disconnected. An identical capacitor is now connected to the first capacitor in parallel. The energy in each of the capacitors is :
3 U/2
U
U/4
U/2

Energy stored in a capacitor is $U = \frac{Q^{2}}{2 C}$ .
As the battery is disconnected, total charge $Q$ is shared equally by two capacitors.
So energy of each capacitor $= \frac{(Q / 2)^{2}}{2 C} = \frac{1}{4} \frac{Q^{2}}{2 C} = \frac{U}{4}$ .