The correct option is A 200 V
The equivalent capacitance of the capacitors joined in parallel is equal to the sum of their individual capacitances.
Let the charge on the capacitors be q1 and q2. Then total charge
Q=Q+Q2
CV=C1V1+C2V2
Since, capacitors are connected in parallel equivalent capacitance is C=C1+C2
V=C1V1+C2V2C1+C2
Given, C1=10μF,V1−250V,C2=5μF,V2=100V
∴V=(10×10−6×250)+(5×10−6×100)(10×10−6+5×10−6)
⇒V=3000×10−615×10−6=200V