A capacitor of capacitance 10μF is charged to 10V. The energy stored in it is
100μJ
500μJ
1000μJ
1μJ
A
500μJ
B
1000μJ
C
1μJ
D
100μJ
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Solution
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Given : C=10μF=10−5FV=10 volts
Energy stored E=12CV2
∴E=12×10−5×102=5×10−4J
⟹E=500μJ
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