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Question

A capacitor of capacitance 10μF is charged to 10V. The energy stored in it is
  1. 100μJ
  2. 500μJ
  3. 1000μJ
  4. 1μJ

A
500μJ
B
1000μJ
C
1μJ
D
100μJ
Solution
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Given : C=10μF=105F V=10 volts
Energy stored E=12CV2
E=12×105×102=5×104 J
E=500μJ

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