A capacitor of capacitance C carrying charge Q is connected to a source of emf E. Finally the charge on capacitor would be :
Q+CE
Q
CE
none of these
A
Q+CE
B
none of these
C
Q
D
CE
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Solution
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As the capacitor is connected to source of emf E so the potential across capacitor becomes constant. i.e is equal to E. So the final charge Qf=CE
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