Question

A capacitor of capacitance $C$ is connected to a cell of $emf$ V and when fully charged, it is disconnected. Now the separation between the plates doubled. The change in flux of electric field through a closed surface enclosing the capacitor is :

• A. Zero
• B. $\frac{CV}{{\epsilon }_0}$
• C. $\frac{CV}{2{\epsilon }_0}$
• D. $\frac{2CV}{{\epsilon }_0}$

Answer 1

Answer: (A)