A capacitor of capacitance C1β=1ΞΌF withstand the maximum voltage V1β=6.0kV while the capacitor of capacitance C2β=2ΞΌF, the maximum voltage V2β=4.0kV. What voltage in Kilo Volt will the system of these two capacitors withstand if they are connected in series?
A
7
B
9
C
8
D
6
Medium
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Solution
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Correct option is B)
Maximum charge capacitance C1β can withstand is Q1β=C1βV1β while capacitance C2β can withstand maximum charge of Q2β=C2βV2β
When C1βΒ andΒ C2β are connected in series the charge on each capacitor is equal and is equal to the maximum charge the combination can withstand, Qmaxβ=C1βV1βΒ β΅C1βV1β<C2βV2β ... for given values
The resultant capacitance of the combination is CRβ=C1β+C2βC2βC1ββ
Qmaxβ=6Γ10β3Β C and CRβ=32βΓ10β6Β F
Maximum voltage that the combination of capacitance can withstand is Vmaxβ=CRβQmaxββ
Vmaxβ=9Β kV
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