A capacitor of capacitance C1=1μF withstand the maximum voltage V1=6.0kV while the capacitor of capacitance C2=2μF, the maximum voltage V2=4.0kV. What voltage in Kilo Volt will the system of these two capacitors withstand if they are connected in series?
A
7
B
9
C
8
D
6
Medium
Open in App
Updated on : 2022-09-05
Solution
Verified by Toppr
Correct option is B)
Maximum charge capacitance C1 can withstand is Q1=C1V1 while capacitance C2 can withstand maximum charge of Q2=C2V2
When C1andC2 are connected in series the charge on each capacitor is equal and is equal to the maximum charge the combination can withstand, Qmax=C1V1∵C1V1<C2V2 ... for given values
The resultant capacitance of the combination is CR=C1+C2C2C1
Qmax=6×10−3C and CR=32×10−6F
Maximum voltage that the combination of capacitance can withstand is Vmax=CRQmax
Vmax=9kV
Solve any question of Electrostatic Potential and Capacitance with:-