A capacitor of capacitance Chas charge Qand stored energy W. If the charge is increased to 2Q, the stored energy would be:
W4
2W
W2
4W
A
W2
B
4W
C
2W
D
W4
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Solution
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We know that the energy stored in a capacitor is given by:
W=Q22C
Now, if the charge Q increases to 2Q,
then the change in energy will be given by:
W′=(2Q)22C
⇒4Q22C=4W
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