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>> $A car moves a distance of 200 m. It cove$

Question

A car moves a distance of 200 m. It covers the first half of the distance at speed 40 km/h and the second half of the distance at speed v. If the average speed is 48 km/h, then the value of v is-

A

50 km/h

B

56 km/h

C

58 km/h

D

60 km/h

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Solution

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Correct option is D)

Given, $D i s t a n c e = 200 m, S p e e d = 40 k m / h$ Average speed = $48 k m / h$

$48 = \frac{2 0 0}{\frac{1 0 0}{4 0} + \frac{1 0 0}{v}} \Rightarrow \frac{1}{4 0} + \frac{1}{v} = \frac{1}{2 4} \Rightarrow v = \frac{1 2 0}{5 - 3} = \frac{1 2 0}{2} \Rightarrow = 60 k m / h$

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