A car -open the top- of mass 9-75 kg is coasting along a level track 1-36 m-s- when it begins to rain hard- The raindrops fall vertically with respect to the ground- When it has collected 0-5 kg of rain- the speed of the car is0-68 m-s1-29 m-s2-48 m-s9-8 m-s

Question

Toppr Admin · Accepted Answer

Initial m1-9-75 kgfinal m-9-75-0-5-10-25m1v1-m2v2-9-75-1-36-10-25-v2v2-1-29 m-s

A car (open at the top) of mass 9.75 kg is coasting along a level track at 1.36 m/s, when it begins to rain hard. The raindrops fall vertically with respect to the ground. When it has collected 0.5 kg of rain, the speed of the car is
0.68 m/s
1.29 m/s
2.48 m/s
9.8 m/s

Initial $m_{1} = 9.75$ kg
final $m = 9.75 + 0.5 = 10.25$
$m_{1} v_{1} = m_{2} v_{2}$
$(9.75) (1.36) = (10.25) v_{2}$
$v_{2} = 1.29$ m/s

A car (open at the top) of mass 9.75 kg is coasting along a level track at 1.36 m/s, when it begins to rain hard. The raindrops fall vertically with respect to the ground. When it has collected 0.5 kg of rain, the speed of the car is0.68 m/s1.29 m/s2.48 m/s9.8 m/s

Initial m1=9.75 kgfinal m=9.75+0.5=10.25m1v1=m2v2(9.75)(1.36)=(10.25)v2v2=1.29 m/s

A car (open at the top) of mass 9.75 kg is coasting along a level track at 1.36 m/s, when it begins to rain hard. The raindrops fall vertically with respect to the ground. When it has collected 0.5 kg of rain, the speed of the car is
0.68 m/s
1.29 m/s
2.48 m/s
9.8 m/s

Initial $m_{1} = 9.75$ kg
final $m = 9.75 + 0.5 = 10.25$
$m_{1} v_{1} = m_{2} v_{2}$
$(9.75) (1.36) = (10.25) v_{2}$
$v_{2} = 1.29$ m/s