A car starts from rest and accelerates uniformly to a speed of $180 k m h^{- 1}$ in $10$ sec. The distance covered by the car in the time interval is :
$300 m$
$500 m$
$250 m$
$200 m$

Question

A car starts from rest and accelerates uniformly to a speed of  180 -km -h-1-  in 10 sec- The distance covered by the car in the time interval is -300- m500 -m250- m200- m

Toppr Admin · Accepted Answer

U-0-xA0-v-180-xA0-180km-h-50m-sTime taken- t-10sa-v-x2212-ut-6010-6ms-x2212-2Distance covered-xA0-s-ut-12at2-0-12-xD7-5-xD7-10-2-5002-x21D2-250m

A car starts from rest and accelerates uniformly to a speed of 180kmh−1 in 10 sec. The distance covered by the car in the time interval is :300m500m250m200m

u=0, v=180 180km/h=50m/sTime taken, t=10sa=v−ut=6010=6ms−2Distance covered s=ut+12at2=0+12×5×(10)2=5002⇒=250m

A car starts from rest and accelerates uniformly to a speed of $180 k m h^{- 1}$ in $10$ sec. The distance covered by the car in the time interval is :
$300 m$
$500 m$
$250 m$
$200 m$

$u = 0$ ,
$v = 180$
$180 k m / h = 50 m / s$
Time taken, $t = 10 s$
$a = \frac{v - u}{t} = \frac{60}{10} = 6 m s^{- 2}$
Distance covered
$s = u t + \frac{1}{2} a t^{2}$
$= 0 + \frac{1}{2} \times 5 \times (10)^{2}$
$= \frac{500}{2} \Rightarrow= 250 m$