A car travels first 100mathrm - km - in 2dfrac - 1 - - 2 - hours and next 30mathrm - km - in dfrac - 1 - - 2 - hour- What is its average speed -dfrac -130-2- km-hdfrac -130-3- km-hdfrac -100-3- km-hNone of these

Question

Toppr Admin · Accepted Answer

Total distance -100-30-130 kmTotal time - 212-12-xA0-52-12 - 62 - 3 hrsAverage speed - 130 -xF7- 3 - 1303 km-h

A car travels first $100 k m$ in $2 \frac{1}{2}$ hours and next $30 k m$ in $\frac{1}{2}$ hour. What is its average speed ?
$\frac{130}{2} k m / h$
$\frac{130}{3} k m / h$
$\frac{100}{3} k m / h$
None of these

Total distance $= 100 + 30 = 130$ km
Total time = $2 \frac{1}{2} + \frac{1}{2}$
= $\frac{5}{2} + \frac{1}{2}$ = $\frac{6}{2}$ = 3 hrs
Average speed = 130 $\div$ 3 = $\frac{130}{3}$ km/h

A car travels first 100km in 212 hours and next 30km in 12 hour. What is its average speed ?1302km/h1303km/h1003km/hNone of these

Total distance =100+30=130 kmTotal time = 212+12= 52+12 = 62 = 3 hrsAverage speed = 130 ÷ 3 = 1303 km/h

A car travels first $100 k m$ in $2 \frac{1}{2}$ hours and next $30 k m$ in $\frac{1}{2}$ hour. What is its average speed ?
$\frac{130}{2} k m / h$
$\frac{130}{3} k m / h$
$\frac{100}{3} k m / h$
None of these

Total distance $= 100 + 30 = 130$ km
Total time = $2 \frac{1}{2} + \frac{1}{2}$
= $\frac{5}{2} + \frac{1}{2}$ = $\frac{6}{2}$ = 3 hrs
Average speed = 130 $\div$ 3 = $\frac{130}{3}$ km/h