A car travels on a straight road from point $A$ to point $B$ in four hours, and then from point $B$ back to point $A$ in six hours. The distance between the two points is $240 k m$ .
Find out the car's average velocity?

Question

A car travels on a straight road from point

A

to point

B

in four hours, and then from point

B

back to point

A

in six hours. The distance between the two points is

240 k m

.
Find out the car's average velocity?

Toppr Admin · Accepted Answer

Total distance traveled by car -xA0- -xA0- -xA0- D-240-240-480 -xA0-kmTotal time taken -xA0- -xA0- -xA0- -xA0- t-4-6-10 -xA0-h-x2234- Average speed of car -Dt-48010-48 -xA0-km-h

A car travels on a straight road from point $A$ to point $B$ in four hours, and then from point $B$ back to point $A$ in six hours. The distance between the two points is $240 k m$ .
What is the car's average speed?

$48 k m / h$
$60 k m / h$
$50 k m / h$
$100 k m / h$
$0 k m / h$

Total distance traveled by car $D = 240 + 240 = 480$ km
Total time taken $t = 4 + 6 = 10$ h
$∴$ Average speed of car $= \frac{D}{t} = \frac{480}{10} = 48$ $k m / h$

A car travels on a straight road from point A to point B in four hours, and then from point B back to point A in six hours. The distance between the two points is 240km.What is the car's average speed?48km/h60km/h50km/h100km/h0km/h

Total distance traveled by car D=240+240=480 kmTotal time taken t=4+6=10 h∴ Average speed of car =Dt=48010=48 km/h

A car travels on a straight road from point $A$ to point $B$ in four hours, and then from point $B$ back to point $A$ in six hours. The distance between the two points is $240 k m$ .
What is the car's average speed?

$48 k m / h$
$60 k m / h$
$50 k m / h$
$100 k m / h$
$0 k m / h$

Total distance traveled by car $D = 240 + 240 = 480$ km
Total time taken $t = 4 + 6 = 10$ h
$∴$ Average speed of car $= \frac{D}{t} = \frac{480}{10} = 48$ $k m / h$