(a) When a card is selected from a pack of $52$ cards the number of possible outcomes is $52$ i.e., the sample space contains $52$ elements
Therefore there are $52$ points in the sample space
(b) Let $A$ be the event in which the card drawn is an ace of spades
Accordingly $n(A)=1$. Since there is only one ace of spade in the deck.
$\therefore P\left(A\right)=\frac{NumberofoutcomesfavourabletoA}{Totalnumberofpossibleoutcomes}=\frac{n\left(A\right)}{n\left(S\right)}=\frac{1}{52}$
(c) (i) Let $E$ be the event in which the card drawn is an ace.
Since there are $4$ aces in a pack of $52$ cards $n(E)=4$
$\therefore P\left(E\right)=\frac{NumberofoutcomesfavourabletoE}{Totalnumberofpossibleoutcomes}=\frac{n\left(E\right)}{n\left(S\right)}=\frac{4}{52}$=$\frac{1}{13}$ 
(ii) Let $F$ be the event in which the card drawn is black
Since there are $26$ black cards in a pack of $52$ cards $n(F)=26$
$\therefore P\left(F\right)=\frac{NumberofoutcomesfavourabletoF}{Totalnumberofpossibleoutcomes}=\frac{n\left(F\right)}{n\left(S\right)}=\frac{26}{52}=\frac{1}{2}$