A cask contains 3parts ale and 1 part porter. How much of the mixture must be drawn off and porter substituted in order that the resulting mixture may be half and half?
$\frac{1}{3}$
$\frac{1}{2}$
$\frac{1}{5}$
$\frac{1}{6}$

Question

Toppr Admin · Accepted Answer

14-12-x21D2-12-1-x21D2-13The given answer is correct-

A cask contains 3parts ale and 1 part porter. How much of the mixture must be drawn off and porter substituted in order that the resulting mixture may be half and half?13121516