A certain ion, B− has a dissociation constant for Arrhenius basic character (2.8×10−7). The equilibrium constant for Lowry-Bronsted basic character is:
2.8×10−7
2.8×107
3.57×10−8
3.57×108
A
3.57×108
B
2.8×107
C
3.57×10−8
D
2.8×10−7
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Solution
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B−Bronstedbase+H+⇌HB;Kb=[HB][B−][H+]......(i) B−Arrhneiusbase+H+⇌HB+OH−;Ka=[HB][OH−][B−]......(ii) By Eqs. (i) and (ii) KaKb=[HB][OH−][B−]×[B−][H+][HB]=[H+][OH−]=Kw........(iii) By Eqs. (i) and (ii) and (iii), Kb=KaKw=2.8×10−710−14=2.8×107
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