A charge 3 coulomb experiences a force 3000 N when placed in a uniform electric field- The potential difference between two points seperated by a distance of 1 cm along the field lines is -10 V90 V1000 V9000 V

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Toppr Admin · Accepted Answer

-Electric force F-qE-given- F-3000N-q-3C-x2234-E-Fq-30003-1000V-m-Potential difference-V-Ed where d-0-01m-x2234-V-1000-xD7-0-01-10V-Ans-A-

A charge $3$ coulomb experiences a force $3000 N$ when placed in a uniform electric field. The potential difference between two points seperated by a distance of $1 c m$ along the field lines is :
$10 V$
$90 V$
$1000 V$
$9000 V$

Electric force $F = q E$

given, $F = 3000 N, q = 3 C$

$∴ E = \frac{F}{q} = \frac{3000}{3} = 1000 V / m$

Potential difference, $V = E d$ where $d = 0.01 m$

$∴ V = 1000 \times 0.01 = 10 V$

Ans:(A)

A charge 3 coulomb experiences a force 3000 N when placed in a uniform electric field. The potential difference between two points seperated by a distance of 1 cm along the field lines is :10 V90 V1000 V9000 V

Electric force F=qE given, F=3000N,q=3C ∴E=Fq=30003=1000V/m Potential difference, V=Ed where d=0.01m ∴V=1000×0.01=10V Ans:(A)

A charge $3$ coulomb experiences a force $3000 N$ when placed in a uniform electric field. The potential difference between two points seperated by a distance of $1 c m$ along the field lines is :
$10 V$
$90 V$
$1000 V$
$9000 V$

Electric force $F = q E$

given, $F = 3000 N, q = 3 C$

$∴ E = \frac{F}{q} = \frac{3000}{3} = 1000 V / m$

Potential difference, $V = E d$ where $d = 0.01 m$

$∴ V = 1000 \times 0.01 = 10 V$

Ans:(A)