A charge 3 coulomb experiences a force 3000N when placed in a uniform electric field. The potential difference between two points seperated by a distance of 1cm along the field lines is :
10V
90V
1000V
9000V
A
9000V
B
1000V
C
10V
D
90V
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Solution
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Electric force F=qE
given, F=3000N,q=3C
∴E=Fq=30003=1000V/m
Potential difference,
V=Ed where d=0.01m
∴V=1000×0.01=10V
Ans:(A)
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