A charge of 0.04C is moving in a magnetic field of 0.02T with a velocity 10m/s in a direction making an angle 30o with the direction of field. The force acting on it will be :
A
4×10−3N
B
2×10−3N
C
zero
D
8×10−3N
Medium
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Updated on : 2022-09-05
Solution
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Correct option is A)
Force on the moving charge is, F=q(v×B)=qvBsinθ=0.04×10×0.02sin30o=0.04×10×0.02×0.5=4×10−3N
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