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# A charge of 0.04C is moving in a magnetic field of 0.02T with a velocity 10m/s in a direction making an angle 30o with the direction of field. The force acting on it will be :4×10−3Nzero8×10−3N2×10−3N

A
2×103N
B
4×103N
C
zero
D
8×103N
Solution
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#### Force on the moving charge is,→F=q(→v×→B)=qvBsinθ=0.04×10×0.02sin30o=0.04×10×0.02×0.5=4×10−3N

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