A charge of 6-25mu C in an electric field is acted upon by a force 2-5N- The potential gradient this point is4times 10-6-V - m4times 10-7-V - m2-5times 10-6-V - m4times 10-5-V - m

Question

Toppr Admin · Accepted Answer

Given force-2-5 -x3BC-we know F-Eq-x21D2-2-5-E-6-25-xA0-x3BC-c-xA0-

A charge of $6.25 μ C$ in an electric field is acted upon by a force $2.5 N$ . The potential gradient at this point is

$4 \times 10^{6} V / m$
$4 \times 10^{7} V / m$
$2.5 \times 10^{- 6} V / m$
$4 \times 10^{5} V / m$

given force $= 2.5$ $μ$
we know $F = E q$
$\Rightarrow 2.5 = E (6.25 μ c)$

A charge of 6.25μC in an electric field is acted upon by a force 2.5N. The potential gradient at this point is4×106V/m4×107V/m2.5×10−6V/m4×105V/m

given force=2.5 μwe know F=Eq⇒2.5=E(6.25 μc)

A charge of $6.25 μ C$ in an electric field is acted upon by a force $2.5 N$ . The potential gradient at this point is

$4 \times 10^{6} V / m$
$4 \times 10^{7} V / m$
$2.5 \times 10^{- 6} V / m$
$4 \times 10^{5} V / m$

given force $= 2.5$ $μ$
we know $F = E q$
$\Rightarrow 2.5 = E (6.25 μ c)$