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The Circular Motion

Question

A charge particle enters into a magnetic field with a velocity vector making an angle of $30^{o}$ with respect to the direction of magnetic field. The path of the particle is:
circular
helical
straight line
elliptical

A

circular

B

straight line

C

helical

D

elliptical

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Solution

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Here velocity vector have two components
(i) v cos $θ$ , parallel to magnetic field
(ii) v sin $θ$ , perpendicular to magnetic field. Due to component v cos $θ$ , the particle will have a linear motion but due to v sin $θ$ , the particle will have simultaneously a circular motion. The resultant of the two is a helical path.

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