A charge Q is placed at a distance a/2 above the centre of the square surface of edge a as shown in the figure. The electric flux through the square surface is:
Q6ϵ0
Q3ϵ0
Q2ϵ0
Qϵ0
A
Q6ϵ0
B
Q3ϵ0
C
Q2ϵ0
D
Qϵ0
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Solution
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Draw an imaginary square enclosing that point charge at the centre.
Then from gauss law, ϕ=Qinϵo
This is the flux passing through all the six surfaces.
Therefore through one surface, 16th of this flux will pass.
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