A charge Q is placed each of the two opposite corners of a square- A charge q is placed each of the other two comers- If the resultant force on each charge q is zero- then -q - sqrt 2 Qq - -sqrt 2 Qq - 2sqrt 2 Qq - -2sqrt 2 Q

Question

Toppr Admin · Accepted Answer

The net force on q at one corner is zero if $_{1} +_{2} +_{3} = 0$
or $F_{1} cos 45^{o}^i - F_{1} sin 45^{o}^j - F_{2}^j + F_{3}^i = 0$
so, $F_{1} cos 45^{o} = - F_{3} . . . . (1)$ and $F_{1} sin 45^{o} = - F_{2} . . . . (2)$
using (1) , $\frac{k q^{2}}{(\sqrt{2} a)^{2}} \times \frac{1}{\sqrt{2}} = - \frac{k q Q}{a^{2}}$
or $q = - 2 \sqrt{2} Q$

A charge Q is placed at each of the two opposite corners of a square. A charge q is placed at each of the other two comers. If the resultant force on each charge q is zero, then :q=√2Qq=−√2Qq=2√2Qq=−2√2Q

The net force on q at one corner is zero if →F1+→F2+→F3=0or F1cos45o^i−F1sin45o^j−F2^j+F3^i=0 so, F1cos45o=−F3....(1) and F1sin45o=−F2....(2)using (1) , kq2(√2a)2×1√2=−kqQa2or q=−2√2Q

A charge Q is placed at each of the two opposite corners of a square. A charge q is placed at each of the other two comers. If the resultant force on each charge q is zero, then :
$q = \sqrt{2} Q$
$q = - \sqrt{2} Q$
$q = 2 \sqrt{2} Q$
$q = - 2 \sqrt{2} Q$