Four chargers $q_{1}=−0.02μC$, $q_{2}=+0.04μC$, $q_{3}=+0.02μC$, and $q_{4}=−0.04μC$ are at the four corners of a square of side $9cm$ . Then the potential at the centre of the square is :

The potential at the origin is zero due to electric field $Eˉ=20i^+30j^ NC_{−1}$ . The potential at point $P(2m,2m)$ is:

Two point charges $q_{1}=2μC$ and $q_{2}=1μC$ are placed at distances $b=1cm$ and $a=2cm$ from the origin on the y and x axes as shown in figure. The electric field vector at point $(a,b)$ will subtend an angle $θ$ with the x - axis given by :

Two concentric, thin metallic spherical shells of radii $R_{1}$and$R_{2}(R_{1}>R_{2})$ bear charges $Q_{1}$ and$Q_{2}$ respectively. Then the potential at radius ‘r’ between $R_{1}$ and $R_{2}$will be $4πϵ_{0}1 $ times

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