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>>Moving Charges and Magnetism
>>Lorentz Force
>> $A charged particle A of charge q = 2 C h$

Question

A charged particle A of charge q = 2 C has velocity v = 100 m/s. When it passes through point A and has velocity in the direction shown. The strength of magnetic field at point B due to this moving charge is (r = 2 m).the agle between them is 30.

42293

A

2.5 $μ$ T

B

5.0 $μ$ T

C

2.0 $μ$ T

D

None

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Updated on : 2022-09-05

Solution

Verified by Toppr

Correct option is A)

$\frac{μ _{0}}{4 π} \frac{q v \times r}{r ^{3}} = \frac{μ _{0}}{4 π} \frac{q v s i n θ}{r ^{2}}$
= $\frac{μ _{0}}{4 π} \frac{2 \times 1 0 0 \times s i n 3 0 ^{0}}{4}$

= $10^{- 7} \times 25$

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