A charged particle A of charge q = 2 C has velocity v = 100 m/s. When it passes through point A and has velocity in the direction shown. The strength of magnetic field at point B due to this moving charge is (r = 2 m).the agle between them is 30.
Open in App
Updated on : 2022-09-05
Verified by Toppr
Correct option is A)
Solve any question of Moving Charges and Magnetism with:-