Question

A charged particle A of charge q = 2 C has velocity v = 100 m/s. When it passes through point A and has velocity in the direction shown. The strength of magnetic field at point B due to this moving charge is (r = 2 m).the agle between them is 30.

42293_a3c6da88eb52467ead7e1a4036060562.png

A
2.5μT
B
5.0μT
C
2.0μT
D
None
Solution
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μ04πqv×rr3=μ04πqvsinθr2
=μ04π2×100×sin3004
=107×25

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