Question

# A charged particle A of charge q = 2 C has velocity v = 100 m/s. When it passes through point A and has velocity in the direction shown. The strength of magnetic field at point B due to this moving charge is (r = 2 m).the agle between them is 30. A
2.5μT
B
5.0μT
C
2.0μT
D
None
Solution
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#### μ04πq→v×→rr3=μ04πqvsinθr2 =μ04π2×100×sin3004 =10−7×25

3
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